This is a direct continuation of my last post on factoring. In this post, we will look into some of the more intricate refinements of Fermat’s Method of Factorization.
After my previous posts (I, II) on perfect partitions of numbers, I continued to play with the relationship between compositions and partitions of different numbers. I ended up stumbling across the following idea: which numbers can be represented as a sum of consecutive positive integers? This seems to be another well-known question, but I haven’t come across it before.
David Lowry-Duda October 17, 2019 at 3:17 pm on Notes from a talk at the Maine-Quebec Number Theory ConferenceThanks Peter! You're right --- and it's a nice reference. 
Peter Humphries October 7, 2019 at 4:03 am on Notes from a talk at the Maine-Quebec Number Theory ConferenceOmega results of this form using this method are presented quite nicely in Chapter 15 of Montgomery and Vaughan; they give applications towards sign changes of the Chebyshev psi function and of partial sums of the Mobius function. 
David Lowry-Duda June 16, 2019 at 1:55 am on Choosing functions and generating figures for “When are there continuous choices for the mean value abscissa?”At first, we chose 2 because it was the other "obvious" point that we hadn't yet specified. We already controlled the values at 0, 1, and 3. But I later realized it doesn't matter what point we choose. What we're really doing is adding one extra degree of freedom and using it to minimize the L2 norm of the derivative ---
PC June 16, 2019 at 1:14 am on Choosing functions and generating figures for “When are there continuous choices for the mean value abscissa?”Why did you choose 2 for the pt in the L2 part? What if you chose 1.5 or something? 
Donna ebert September 27, 2018 at 3:55 pm on AboutI appreciate your taking the time to reply. The version of FreeCell I play online does count taking a card from the tableau (and the Freecells) as a move when adding them to the foundation. I never realized others did not. David Lowry-Duda (mixedmath) September 27, 2018 at 8:20 am on AboutI believe you are referring to: this post on MathSE. Yes, that's right. In the typical language, a "move" consists of one mouse-click-and-drag action. When there are open freecells, it is possible to move multiple cards using one mouse operation (as a shortcut to doing all the card moves individually). As an example, if all 4 freecells are open, you ---Donna September 27, 2018 at 1:38 am on AboutI see nowhere to submit an email so I am asking my question here. On another site you answered a question about the average number of moves to solve Freecell. You gave an in-depth answer about the studies that had been done (thank you) which was 45. What I cannot comprehend is how anyone can move 52 cards, one at ---David Lowry-Duda (mixedmath) September 24, 2018 at 6:33 pm on An intuitive introduction to calculusThank you. You could also write $P(t) = ae^{kt + C_1}$. But this may give the impression that $a$ and $C_1$ carry different data --- but they don't. To see the equivalence, you can write $ae^{kt + C_1} = a e^{kt} e^{C_1} = (a e^{C_1}) e^{kt} = A e^{kt}$, where $A = a e^{C_1}$. There are two fundamental degrees of ---
Luis Alberto Torres Cruz September 23, 2018 at 9:50 am on An intuitive introduction to calculusGreat post! Thank you for taking the time to write this. Regarding the example on population growth, you state that if P'(t) = k*P(t), then P(t) = ae^(kt). But wouldn't a more general expression be: P(t) = ae^(kt+C1), where C1 is a constant? David Lowry-Duda June 9, 2018 at 7:31 am on Math 420: First Week Homework and ReferencesYes, you're right. Thank you for pointing that out. I've now edited it.