## Mathematics Category Archive

Below you will find the most recent posts tagged “Mathematics”, arranged in reverse chronological order.

Below you will find the most recent posts tagged “Mathematics”, arranged in reverse chronological order.

Posted in Mathematics
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This is the final chapter in my series about the state of internet fora, and Math.SE and StackOverflow in particular. The previous chapters are Challenges Facing Community Cohesion and Ghosts of Forums Past. Unlike the previous entries, this also sits on Meta.Math.SE (and was posted there a week before here). (As I write this as a moderator of Math.SE, I refer to the Math.SE community as “we”, “us”, and “our” community).

A couple of weeks ago, there was a proposal on meta.Math.SE to introduce a third level of math site to the SE network. Many members of the the MathSE community have reacted very positively to this proposal, to the extent that even some of the moderators have considered throwing their weight behind it.

But a *NoviceMathSE site would be doomed to fail, and such a separation would not solve the underlying problems facing the site.*

To explain my point of view, we need to examine more closely the arguments in favor of NoviceMathSE.

This is the second in a miniseries of posts on internet fora, and Math.SE and StackOverflow in particular. In the previous entry in the miniseries, I described some of the common major problems facing community cohesion. I claimed that when communities get large, they tend to fracture and the ratio of meaningful communication to noise plummets. To combat this tendency, communities use some mixture of core moderation, peer moderation, membership requirements, or creating subcommunities/splitting off in to other communities.

In this chapter I focus more on Math.SE and StackOverflow. Math.SE is now experiencing growing pains and looking for solutions. But many users of Math.SE have little involvement in the rest of the StackExchange network and are mostly unaware of the fact that StackOverflow has already encountered and passed many of the same trials and tribulations (with varying degrees of success).

Thinking more broadly, many communities have faced these same challenges. Viewed from the point of view from the last chapter, it may appear that there are only a handful of tools a community might use to try to retain group cohesion. Yet it is possible to craft clever mixtures of these tools synergistically. The major reason the StackExchange model has succeeded where other fora have stalled (or failed outright) is through its innovations on the implementation of communition cohesion strategies while still allowing essentially anyone to visit the site.

Slashdot^{1} popularized the idea of associating imaginary internet points to different users. It was called *karma*. You got karma if other users rated your comments or submissions well, and lost karma if they rated your posts as poor. But perhaps most importantly, each user can set a threshold for minimum scores of content to see. Thus if people have reasonable thresholds and you post crap, then most people won’t even see it after it’s scored badly.

In about a month, Math.StackExchange will turn 8. Way back when I was an undergrad, I joined the site. This was 7 years ago, during the site’s first year.

Now with some perspective as a frequent contributor/user/moderator of various online newsgroups and fora, I want to take a moment to examine the current state of Math.SE.

To a certain extent, this is inspired by Joel Spolsky’s series of posts on StackOverflow (which he is currently writing and sending out). But this is also inspired by recent discussion on Meta.Math.SE. As I began to collect my thoughts to make a coherent reply, I realized that I have a lot of thoughts, and a lot to say.

So this is chapter one of a miniseries of writings on internet fora, and Math.SE and StackOverflow in particular.

Tom Hulse, Chan Ieong Kuan, Alex Walker, and I have just uploaded a new paper to the arXiv titled *A Shifted Sum for the Congruent Number Problem*. In this charming, short paper, we investigate a particular sum of terms which are products of square-indicator functions and show that its asymptotics are deeply connected to congruent numbers. This note serves to describe and provide additional context for these results. (This note is also available as a pdf).

We consider some triangles. There are many right triangles, such as the triangle with sides $(3, 4, 5)$ or the triangle with sides $(1, 1, \sqrt{2})$. We call a right triangle *rational* when all its side lengths are rational numbers. For illustration, $(3, 4, 5)$ is rational, while $(1, 1, \sqrt{2})$ is not. $\DeclareMathOperator{\sqfree}{sqfree}$

There is mythology surrounding rational right triangles. According to legend, the ancient Greeks, led both philosophcally and mathematically by Pythagoras (who was the first person to call himself a philosopher and essentially the first to begin to distill and codify mathematics), believed all numbers and quantities were ratios of integers (rational). When a disciple of Pythagoras named Hippasus found that the side lengths of the right triangle $(1, 1, \sqrt{2})$ were not rational multiples of each other, the other followers of Pythagoras killed him by casting him overboard while at sea for having produced an element which contradicted the gods. (It with some irony that we now attribute this as a simple consequence of the Pythagorean Theorem).

This mythology is uncertain, but what is certain is that even the ancient Greeks were interested in studying rational right triangles, and they began to investigate what we now call the Congruent Number Problem. By the year 972 the CNP appears in Arabic manuscripts in (essentially) its modern formulation. The *Congruent Number Problem* (CNP) may be the oldest unresolved math problem.

We call a positive rational number $t$ *congruent* if there is a rational right triangle with area $t$. The triangle $(3,4,5)$ shows that $6 = 3 \cdot 4 / 2$ is congruent. The CNP is to describe all congruent numbers. Alternately, the CNP asks whether there is an algorithm to show definitively whether or not $t$ is a congruent number for any $t$.

We can reduce the problem to a statement about integers. If the rational number $t = p/q$ is the area of a triangle with legs $a$ and $b$, then the triangle $aq$ and $bq$ has area $tq^2 = pq$. It follows that to every rational number there is an associated squarefree integer for which either both are congruent or neither are congruent. Further, if $t$ is congruent, then $ty^2$ and $t/y^2$ are congruent for any integer $y$.

We may also restrict to integer-sided triangles if we allow ourselves to look for those triangles with squarefree area $t$. That is, if $t$ is the area of a triangle with rational sides $a/A$ and $b/B$, then $tA^2 B^2$ is the area of the triangle with integer sides $aB$ and $bA$.

It is in this form that we consider the CNP today.

Congruent Number ProblemGiven a squarefree integer $t$, does there exist a triangle with integer side lengths such that the squarefree part of the area of the triangle is $t$?

We will write this description a lot, so for a triangle $T$ we introduce the notation

\begin{equation}

\sqfree(T) = \text{The squarefree part of the area of } T.

\end{equation}

For example, the area of the triangle $T = (6, 8, 10)$ is $24 = 6 \cdot 2^2$, and so $\sqfree(T) = 6$. We should expect this, as $T$ is exactly a doubled-in-size $(3,4,5)$ triangle, which also corresponds to the congruent number $6$. Note that this allows us to only consider primitive right triangles.

Let $\tau(n)$ denote the square-indicator function. That is, $\tau(n)$ is $1$ if $n$ is a square, and is $0$ otherwise. Then the main result of the paper is that the sum

\begin{equation}

S_t(X) := \sum_{m = 1}^X \sum_{n = 1}^X \tau(m-n)\tau(m)\tau(nt)\tau(m+n)

\end{equation}

is related to congruent numbers through the asymptotic

\begin{equation}

S_t(X) = C_t \sqrt X + O_t\Big( \log^{r/2} X\Big),

\end{equation}

where

\begin{equation}

C_t = \sum_{h_i \in \mathcal{H}(t)} \frac{1}{h_i}.

\end{equation}

Each $h_i$ is a hypotenuse of a primitive integer right triangle $T$ with $\sqfree(T) = t$. Each hypotnesue will occur in a pair of similar triangles $(a,b, h_i)$ and $(b, a, h_i)$; $\mathcal{H}(t)$ is the family of these triangles, choosing only one triangle from each similar pair. The exponent $r$ in the error term is the rank of the elliptic curve

\begin{equation}

E_t(\mathbb{Q}): y^2 = x^3 – t^2 x.

\end{equation}

What this says is that $S_t(X)$ will have a main term if and only if $t$ is a congruent number, so that computing $S_t(X)$ for sufficiently large $X$ will show whether $t$ is congruent. (In fact, it’s easy to show that $S_t(X) \neq 0$ if and only if $t$ is congruent, so the added value here is the nature of the asymptotic).

We should be careful to note that this does not solve the CNP, since the error term depends in an inexplicit way on the desired number $t$. What this really means is that we do not have a good way of recognizing when the first nonzero term should occur in the double sum. We can only guarantee that for any $t$, understanding $S_t(X)$ for sufficiently large $X$ will allow one to understand whether $t$ is congruent or not.

There are four primary components to this result:

- There is a bijection between primitive integer right triangles $T$ with

$\sqfree(T) = t$ and arithmetic progressions of squares $m^2 – tn^2, m^2,

m^2 + tn^2$ (where each term is itself a square). - There is a bijection between primitive integer right triangles $T$ with

$\sqfree(T) = t$ and points on the elliptic curve $E_t(\mathbb{Q}): y^2 = x^3

– t x$ with $y \neq 0 $. - If the triangle $T$ corresponds to a point $P$ on the curve $E_t$, then

the size of the hypotenuse of $T$ can be bounded below by $H(P)$, the

(naive) height of the point on the elliptic curve. - Néron (and perhaps Mordell, but I’m not quite fluent in the initial

history of the theory of elliptic curves) proved strong (upper) bounds on

the number of points on an elliptic curve up to a given height. (In fact,

they proved asymptotics which are much stronger than we use).

In this paper, we use $(1)$ to relate triangles $T$ to the sum $S_t(X)$ and we use $(2)$ to relate these triangles to points on the elliptic curve. Tracking the exact nature of the hypotenuses through these bijections allows us to relate the sum to certain points on elliptic curves. In order to facilitate the tracking of these hypotenuses, we phrase these bijections in slightly different ways than have appeared in the literature. By $(3)$ and $(4)$, we can bound the number and size of the hypotenuses which appear in terms of numbers of points on the elliptic curve up to a certain height. Intuitively this is why the higher the rank of the elliptic curve (corresponding roughly to the existence of many more points on the curve), the worse the error term in our asymptotic.

I would further conjecture that the error term in our asymptotic is essentially best-possible, even though we have thrown away some information in our proof.

We are not the first to note either the bijection between triangles $T$ and arithmetic progressions of squares or between triangles $T$ and points on a particular elliptic curve. The first is surely an ancient observation, but I don’t know who first considered the relation to elliptic curves. But it’s certain that this was a fundamental aspect in Tunnell’s famous work *A Classical Diophantine Problem and Modular Forms of Weight 3/2* from 1983, where he used the properties of the elliptic curve $E_t$ to relate the CNP to the Birch and Swinnerton-Dyer Conjecture.

One statement following from the Birch and Swinnerton-Dyer conjecture (BSD) is that if an elliptic curve $E$ has rank $r$, then the $L$-function $L(s, E)$ has a zero of order $r$ at $1$. The relation between lots of points on the curve and the existence of a zero is intuitive from the approximate relation that

\begin{equation}

L(1, E) \approx \lim_{X} \prod_{p \leq X} \frac{p}{\#E(\mathbb{F}_p)},

\end{equation}

so if $E$ has lots and lots of points then we should expect the multiplicands to be very small.

On the other hand, the elliptic curve $E_t: y^2 = x^3 – t^2 x$ has the interesting property that any point with $y \neq 0$ generates a free group of points on the curve. From the bijections alluded to above, a primitive right integer triangle $T$ with $\sqfree(T) = t$ corresponds to a point on $E_t$ with $y \neq 0$, and thus guarantees that there are lots of points on the curve. Tunnell showed that what I described as “lots of points” is actually enough points that $L(1, E)$ must be zero (assuming the relation between the rank of the curve and the value of $L(1, E)$ from BSD).

Tunnell proved that if BSD is true, then $L(1, E) = 0$ if and only if $n$ is a congruent number.

Yet for any elliptic curve we know how to compute $L(1, E)$ to guaranteed accuracy (for instance by using Dokchitser’s algorithm). Thus a corollary of Tunnell’s theorem is that BSD implies that there is an algorithm which can be used to determine definitively whether or not any particular integer $t$ is congruent.

This is the state of the art on the congruent number problem. Unfortunately, BSD (or even the somewhat weaker between BSD and mere nonzero rank of elliptic curves as is necessary for Tunnell’s result for the CNP) is quite far from being proven.

In this context, the main result of this paper is not as effective at actually determining whether a number is congruent or not. But it does have the benefit of not relying on any unknown conjecture.

And there is some potential follow-up questions. The sum $S_t(X)$ appears as an integral transform of the multiple Dirichlet series

\begin{equation}

\sum_{m,n} \frac{\tau(m-n)\tau(m)\tau(nt)\tau(m+n)}{m^s n^w}

\approx

\sum_{m,n} \frac{r_1(m-n)r_1(m)r_1(nt)r_1(m+n)}{m^s n^w},

\end{equation}

where $r_1(n)$ is $1$ if $n = 0$ or $2$ if $n$ is a positive square, and $0$ otherwise. Then $r_1(n)$ appears as the Fourier coefficients of the half-integral weight standard theta function

\begin{equation}

\theta(z)

= \sum_{n \in \mathbb{Z}} e^{2 \pi i n^2 z}

= \sum_{n \geq 0} r_1(n) e^{2 \pi i n z},

\end{equation}

and $S_t(X)$ is a shifted convolution sum coming from some products of modular forms related to $\theta(z)$.

It may be possible to gain further understanding of the behavior of $S_t(X)$ (and therefore the congruent number problem) by studying the shifted convolution as coming from theta functions.

I would guess that there is a deep relation to Tunnell’s analysis in his 1983 paper, as in some sense he constructs appropriate products of three theta functions and uses them centrally in his proof. But I do not understand this relationship well enough yet to know whether it is possible to deepen our understanding of the CNP, BSD, or Tunnell’s proof. That is something to explore in the future.

Posted in Expository, Math.NT, Mathematics
Tagged congruent number problem, math paper
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On 19 March I gave a talk at the 32nd Automorphic Forms Workshop, which ishosted by Tufts this year. The content of the talk concerned counting points on hyperboloids, and inparticular counting points on the three dimensional hyperboloid

$$\begin{equation}

X^2 + Y^2 = Z^2 + h

\end{equation}$$

for any fixed integer $h$. But thematically, I wanted to give another concrete example of using modularforms to compute some sort of arithmetic data, and to mention how the perhapsapparently unrelated topic of spectral theory appears even in such an arithmeticapplication.

Somehow, starting from counting points on $X^2 + Y^2 = Z^2 + h$ (which appearssimple enough on its own that I could probably put this in front of anelementary number theory class and they would feel comfortable experimentingaway on the topic), one gets to very scary-looking expressions like

$$\begin{equation}

\sum_{t_j}

\langle P_h^k, \mu_j \rangle

\langle \theta^2 \overline{\theta} y^{3/4}, \mu_j \rangle +

\sum_{\mathfrak{a}}\int_{(1/2)}

\langle P_h^k, E_h^k(\cdot, u) \rangle

\langle \theta^2 \overline{\theta} y^{3/4}, E_h^k(\cdot, u) \rangle du,

\end{equation}$$

which is full of lots of non-obvious symbols and is generically intimidating.

Part of the theme of this talk is to give a very direct idea of how one gets tothe very complicated spectral expansion from the original lattice-countingproblem. Stated differently, perhaps part of the theme is to describe a simple-lookingnail and a scary-looking hammer, and show that the hammer actually works quitewell in this case.

The slides for this talk are available here.

Posted in Expository, Math.NT, Mathematics
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[This note is more about modeling some of the mathematics behind political events than politics themselves. And there are pretty pictures.]

Gerrymandering has become a recurring topic in the news. The Supreme Court of the US, as well as more state courts and supreme courts, is hearing multiple cases on partisan gerrymandering (all beginning with a case in Wisconsin).

Intuitively, it is clear that gerrymandering is bad. It allows politicians to choose their voters, instead of the other way around. And it allows the majority party to quash minority voices.

But how can one identify a gerrymandered map? To quote Justice Kennedy in his Concurrence the 2004 Supreme Court case Vieth v. Jubelirer:

When presented with a claim of injury from partisan gerrymandering, courts confront two obstacles. First is the lack of comprehensive and neutral principles for drawing electoral boundaries. No substantive definition of fairness in districting seems to command general assent. Second is the absence of rules to limit and confine judicial intervention. With uncertain limits, intervening courts–even when proceeding with best intentions–would risk assuming political, not legal, responsibility for a process that often produces ill will and distrust.

Later, he adds to the first obstacle, saying:

The object of districting is to establish “fair and effective representation for all citizens.” Reynolds v. Sims, 377 U.S. 533, 565—568 (1964). At first it might seem that courts could determine, by the exercise of their own judgment, whether political classifications are related to this object or instead burden representational rights. The lack, however, of any agreed upon model of fair and effective representation makes this analysis difficult to pursue.

From Justice Kennedy’s Concurrence emerges a theme — a “workable standard” of identifying gerrymandering would open up the possibility of limiting partisan gerrymandering through the courts. Indeed, at the core of the Wisconsin gerrymandering case is a proposed “workable standard”, based around the **efficiency gap.**

In 1971, American economist Thomas Schelling (who later won the Nobel Prize in Economics in 2005) published *Dynamic Models of Segregation* (Journal of Mathematical Sociology, 1971, Vol 1, pp 143–186). He sought to understand why racial segregation in the United States seems so difficult to combat.

He introduced a simple model of segregation suggesting that even if each individual person doesn’t mind living with others of a different race, they might still *choose* to segregate themselves through mild preferences. As each individual makes these choices, overall segregation increases.

I write this post because I wondered what happens if we adapt Schelling’s model to instead model a state and its district voting map. In place of racial segregation, I consider political segregation. Supposing the district voting map does not change, I wondered how the efficiency gap will change over time as people further segregate themselves.

It seemed intuitive to me that political segregation (where people who had the same political beliefs stayed largely together and separated from those with different political beliefs) might correspond to more egregious cases of gerrymandering. But to my surprise, I was (mostly) wrong.

Let’s set up and see the model.

Posted in Expository, Mathematics, Politics, Programming, Python
Tagged gerrymandering, python, Thomas Schelling
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I’m in San Diego, and it’s charming here. (It’s certainly much nicer outside than the feet of snow in Boston. I’ve apparently brought some British rain with me, though).

Today I give a talk on counting lattice points on one-sheeted hyperboloids. These are the shapes described by

$$ X_1^2 + \cdots + X_{d-1}^2 = X_d^2 + h,$$

where $h > 0$ is a positive integer. The question is: how many lattice points $x$ are on such a hyperboloid with $| x |^2 \leq R$; or equivalently, how many lattice points are on such a hyperboloid and contained within a ball of radius $\sqrt R$ centered at the origin?

I describe my general approach of transforming this into a question about the behavior of modular forms, and then using spectral techniques from the theory of modular forms to understand this behavior. This becomes a question of understanding the shifted convolution Dirichlet series

$$ \sum_{n \geq 0} \frac{r_{d-1}(n+h)r_1(n)}{(2n + h)^s}.$$

Ultimately this comes from the modular form $\theta^{d-1}(z) \overline{\theta(z)}$, where

$$ \theta(z) = \sum_{m \in \mathbb{Z}} e^{2 \pi i m^2 z}.$$

Here are the slides for this talk. Note that this talk is based on chapter 5 of my thesis, and (hopefully) soon a preprint of this chapter ready for submission will appear on the arXiv.

Posted in Math.NT, Mathematics
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This is a very short post in my collection working through this year’s Advent of Code challenges. Unlike the previous ones, this has no mathematical comments, as it was a very short exercise. This notebook is available in its original format on my github.

Given a list of strings, determine how many strings have no duplicate words.

This is a classic problem, and it’s particularly easy to solve this in python. Some might use `collections.Counter`

, but I think it’s more straightforward to use sets.

The key idea is that the set of words in a sentence will not include duplicates. So if taking the set of a sentence reduces its length, then there was a duplicate word.

In [1]:

```
with open("input.txt", "r") as f:
lines = f.readlines()
def count_lines_with_unique_words(lines):
num_pass = 0
for line in lines:
s = line.split()
if len(s) == len(set(s)):
num_pass += 1
return num_pass
count_lines_with_unique_words(lines)
```

Out[1]:

I think this is the first day where I would have had a shot at the leaderboard if I’d been gunning for it.

Let’s add in another constraint. Determine how many strings have no duplicate words, even after anagramming. Thus the string

```
abc bac
```

is not valid, since the second word is an anagram of the first. There are many ways to tackle this as well, but I will handle anagrams by sorting the letters in each word first, and then running the bit from part 1 to identify repeated words.

In [2]:

```
with open("input.txt", "r") as f:
lines = f.readlines()
sorted_lines = []
for line in lines:
sorted_line = ' '.join([''.join(l) for l in map(sorted, line.split())])
sorted_lines.append(sorted_line)
sorted_lines[:2]
```

Out[2]:

In [3]:

```
count_lines_with_unique_words(sorted_lines)
```

Out[3]:

This is the third notebook in my posts on the Advent of Code challenges. The notebook in its original format can be found on my github.

Numbers are arranged in a spiral

```
17 16 15 14 13
18 5 4 3 12
19 6 1 2 11
20 7 8 9 10
21 22 23---> ...
```

Given an integer n, what is its Manhattan Distance from the center (1) of the spiral? For instance, the distance of 3 is $2 = 1 + 1$, since it’s one space to the right and one space up from the center.

Here’s my idea. The bottom right corner of the $k$th layer is the integer $(2k+1)^2$, since that’s how many integers are contained within that square. The other three corners in that layer are $(2k+1)^2 – 2k, (2k+1)^2 – 4k$, and $(2k+1)^2 – 6k$. Finally, the closest spot on the $k$th layer to the origin is at distance $k$: these are the four “axis locations” halfway between the corners, at $(2k+1)^2 – k, (2k+1)^2 – 3k, (2k+1)^2 – 5k$, and $(2k+1)^2 – 7k$.

For instance when $k = 1$, the bottom right is $(2 + 1)^2 = 9$, and the four “axis locations” are $9 – 1, 9 – 3, 9-5$, and $9-7$. The “axis locations” are $k$ away, and the corners are $2k$ away.

So I will first find which layer the number is on. Then I’ll figure out which side it’s on, and then how far away it is from the nearest “axis location” or “corner”.

My given number happens to be 289326.

In [1]:

```
import math
def find_lowest_larger_odd_square(n):
upper = math.ceil(n**.5)
if upper %2 == 0:
upper += 1
return upper
```

In [2]:

```
assert find_lowest_larger_odd_square(39) == 7
assert find_lowest_larger_odd_square(26) == 7
assert find_lowest_larger_odd_square(25) == 5
```

In [3]:

```
find_lowest_larger_odd_square(289326)
```

Out[3]:

In [4]:

```
539**2 - 289326
```

Out[4]:

It happens to be that our integer is very close to an odd square.

The square is $539^2$, and the distance to that square is $538$ from the center.

Note that $539 = 2(269) + 1$, so this is the $269$th layer of the square.

The previous corner to $539^2$ is $539^2 – 538$, and the previous corner to that is $539^2 – 2\cdot538 = 539^2 – 1076$.

This is the nearest corner.

How far away from the square is this corner?

Posted in Expository, Programming, Python
Tagged advent of code, number spiral, python
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This is the second notebook in my posts on the Advent of Code challenges. This notebook in its original format can be found on my github.

You are given a table of integers. Find the difference between the maximum and minimum of each row, and add these differences together.

There is not a lot to say about this challenge. The plan is to read the file linewise, compute the difference on each line, and sum them up.

In [1]:

```
with open("input.txt", "r") as f:
lines = f.readlines()
lines[0]
```

Out[1]:

In [2]:

```
l = lines[0]
l = l.split()
l
```

Out[2]:

In [3]:

```
def max_minus_min(line):
'''Compute the difference between the largest and smallest integer in a line'''
line = list(map(int, line.split()))
return max(line) - min(line)
def sum_differences(lines):
'''Sum the value of `max_minus_min` for each line in `lines`'''
return sum(max_minus_min(line) for line in lines)
```

In [4]:

```
testcase = ['5 1 9 5','7 5 3', '2 4 6 8']
assert sum_differences(testcase) == 18
```

In [5]:

```
sum_differences(lines)
```

Out[5]:

In line with the first day’s challenge, I’m inclined to ask what we should “expect.” But what we should expect is not well-defined in this case. Let us rephrase the problem in a randomized sense.

Suppose we are given a table, $n$ lines long, where each line consists of $m$ elements, that are each uniformly randomly chosen integers from $1$ to $10$. We might ask what is the expected value of this operation, of summing the differences between the maxima and minima of each row, on this table. What should we expect?

As each line is independent of the others, we are really asking what is the expected value across a single row. So given $m$ integers uniformly randomly chosen from $1$ to $10$, what is the expected value of the maximum, and what is the expected value of the minimum?

Let’s begin with the minimum. The minimum is $1$ unless all the integers are greater than $2$. This has probability

$$ 1 – \left( \frac{9}{10} \right)^m = \frac{10^m – 9^m}{10^m}$$

of occurring. We rewrite it as the version on the right for reasons that will soon be clear.

The minimum is $2$ if all the integers are at least $2$ (which can occur in $9$ different ways for each integer), but not all the integers are at least $3$ (each integer has $8$ different ways of being at least $3$). Thus this has probability

$$ \frac{9^m – 8^m}{10^m}.$$

Continuing to do one more for posterity, the minimum is $3$ if all the integers are at least $3$ (each integer has $8$ different ways of being at least $3$), but not all integers are at least $4$ (each integer has $7$ different ways of being at least $4$). Thus this has probability

$$ \frac{8^m – 7^m}{10^m}.$$

And so on.

Recall that the expected value of a random variable is

$$ E[X] = \sum x_i P(X = x_i),$$

so the expected value of the minimum is

$$ \frac{1}{10^m} \big( 1(10^m – 9^m) + 2(9^m – 8^m) + 3(8^m – 7^m) + \cdots + 9(2^m – 1^m) + 10(1^m – 0^m)\big).$$

This simplifies nicely to

$$ \sum_ {k = 1}^{10} \frac{k^m}{10^m}. $$

The same style of thinking shows that the expected value of the maximum is

$$ \frac{1}{10^m} \big( 10(10^m – 9^m) + 9(9^m – 8^m) + 8(8^m – 7^m) + \cdots + 2(2^m – 1^m) + 1(1^m – 0^m)\big).$$

This simplifies to

$$ \frac{1}{10^m} \big( 10 \cdot 10^m – 9^m – 8^m – \cdots – 2^m – 1^m \big) = 10 – \sum_ {k = 1}^{9} \frac{k^m}{10^m}.$$

Subtracting, we find that the expected difference is

$$ 9 – 2\sum_ {k=1}^{9} \frac{k^m}{10^m}. $$

From this we can compute this for each list-length $m$. It is good to note that as $m \to \infty$, the expected value is $9$. Does this make sense? Yes, as when there are lots of values we should expect one to be a $10$ and one to be a $1$. It’s also pretty straightforward to see how to extend this to values of integers from $1$ to $N$.

Looking at the data, it does not appear that the integers were randomly chosen. Instead, there are very many relatively small integers and some relatively large integers. So we shouldn’t expect this toy analysis to accurately model this problem — the distribution is definitely not uniform random.

But we can try it out anyway.

Posted in Expository, Programming, Python
Tagged advent of code, Programming, python
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